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I don't like the title 'injections are invertible'. To me invertible means to have an inverse, (what the paragraph I am critisising calls a 'full inverse').
I would prefer something like 'injections have left inverses' or maybe 'injections are left-invertible'. Then the section on bijections could have 'bijections are invertible', and the section on surjections could have 'surjections have right inverses'. — Preceding unsigned comment added by 80.229.247.11 (talk) 06:02, 14 April 2006 (UTC)
I don't like that the main heading of this article is "Injective function" and not "One-to-one function". I am not a PHD or anything, but it seems to me that one-to-one function is the term that is used within highschool and college mathematics, not "Injective function". Psyadam 20:23, 29 March 2007 (UTC)Adam Henderson, March 29, 2007
I added the paragraph in the first screen with the ugly notice in parenthesis, in hopes that someone of greater mathematical expertise will soon happen upon it and fix/remove the notice and accompanying text, while providing some explanation in the article that clarifies a possible misunderstanding that readers (especially new to the subject) might have in understanding an injection.
I'm attempting to address the following question a student reader might have:
"What if a function is defined as:
F(x) : A -> B
where A = {1} and B = {a,b,c,d}
and the function F is defined as:
1 -> a
1 -> b
1 -> c
1 -> d
Then isn't this 'function' F an injection according to the mathematical rule invoked to determine the property of injection?"
The problem here (as I understand it) is that a mathematical function cannot be designated as having multiple outputs, unless they are specified as an ordered set. So in the example given,
1 -> (a,b,c,d)
would be the appropriate way to define the desired function, with F(x) : A -> BxBxBxB serving as the function's context (or perhaps a better revision, F(x) : A -> {a}x{b}x{c}x{d}).
Austinflorida 20:13, 23 April 2007 (UTC)
Yep. They don't even have to be ordered or numbered, you can have a variable amount of outputs in the form of an unordered set (set operators like "union" works like this). Of course, they will then map the parameter to the set of sets, so the argument is the same.
Being a comp sci kiddie, I don't have the hubris to change it, but it looks right to me. Maybe except for the counter-intuitive bit :P
80.203.114.197 11:52, 29 April 2007 (UTC)
I removed the paragraph on the first screen with the ugly notice in parentheses. Although correct, it badly disrupted the flow of the article, and the issue of whether a function can have multiple outputs is already answered on the first page of the article function, which is conspicuously liked to in this article. Besides, if a student conceives of a multivalued "function" such as the one described by Austinflorida as being injective, they will be absolutely correct, so there's no real danger of confusion here. If it's still an issue, a link to the article Multivalued function would probably be more appropriate than an exposition on the page such as the one provided here. 70.58.35.214 10:53, 30 April 2007 (UTC)
All examples given by functions were bijective, so I replaced exp's codomain R+ by R. I hope that's okay. Tendays 11:20, 28 October 2007 (UTC)
How frequent is the notation f: X ↣ Y ? I'm a professional mathematician and I never encountered it. On the other hand I've sometimes seen . 82.229.188.151 (talk) 16:07, 12 March 2012 (UTC)
Sorry, are the number of injective functions from X to Y (m in X, n in Y) n^m? I thought that was functions in general. What about (n!/((n-m)!)) ?
Physicproducer (talk) 00:26, 21 November 2012 (UTC)
The 3rd paragraph has real problems, I think. I'm not a mathematician, or even skilled in the art but please consider the following. "A function f that is not injective is sometimes called many-to-one. However, this terminology is also sometimes used to mean "single-valued", i.e., each argument is mapped to at most one value; this is the case for any function, but is used to stress the opposition with multi-valued functions." (as of Nov 1, 2013) 1. I find "this terminology" confusing, in the second sentence. The entire first sentence is jargon laden so which "terminology" is being specified? I do know what the sentence means, but believe it WILL confuse many others...Why not say something like: "However "many-to-one" is sometimes used to mean "all-to-one", i.e. all arguments are mapped to the same single value." I also suggest removal of the "at most", since, in my ignorance, I don't believe you map can an argument to null, so it is NOT "at most one", it is "exactly one". I am not confident enough in my knowledge here to make the change. Someone help, please? 2. The second part is really terrible and must be fixed. It seems to have been written by a non-English speaker (non-native?). Opposition???? This is awful. First: WHAT is used to stress the opposition? Second "stress the opposition" is virtually incomprehensible and terrible usage (did author mean "stress the contrast" or simply "contrast x with"? (I am not clear what is supposedly "used" here). Third use of the phrase "multivalued functions" is really going to confuse anyone that knows that functions are NOT multivalued. (see Multivalued_function). It seems this clause is saying that even though it isn't saying anything, it is used anyway. I am removing the clause, perhaps someone can fix what was being communicated and add another sentence here about contrast with multivalued functions (which are not functions). Thanks.Abitslow (talk) 23:33, 1 November 2013 (UTC)
Injective relation redirects to this article. A function is a particular type of relation and the injective property is the same for both. Inclusive language could define injective for a relation, then apply the same condition for an injective function. The influence of software pushes mathematics toward relations, though the general theory has had a century and a half to develop. As textbooks such as those by Gunther Schmidt become known, the narrow focus on univalent relations (functions) will be broadened. — Rgdboer (talk) 23:38, 5 September 2018 (UTC)
I didn't except anyone would dispute this point, so to prevent stubbornness or edit-warring, here are 38 sources (17 links) explaining that choice isn't needed for left inverses of nonempty injections, or to choose ONE element from a single set, or even one element from each set in a finite family of nonempty sets, even if those are infinite since it follows from a deduction rule of first-order logic:
1. Math.SE: "That is, there is no need for the Axiom of Choice in order to select an element form finitely many nonempty sets. In particular, you do not need the Axiom of Choice to show that you can choose a real number (a single set)."
2-6. MO: See answers 1-4 + Mummert's comment ("I think your first point is the main one for the question. It's alluding to the "existential elimination" inference rule, which says that from the assumption ∃xA(x), you can assert A(c) for some new constant c. The soundness of the rule is a direct consequence of the way semantics for first-order logic are defined."); 4: "The Axiom of Choice does not allow to "choose" a choice function, it only says that a choice function exists. To show that a choice function for a single nonempty set exists, you do not need to "choose" an element in the set, it is enough to show that at least one element exists (i.e. the set is nonempty). Every element in the set will give a different choice function."
7. Annoying Precision: "On the other hand, every monomorphism in Set (edit: with non-empty domain!) is split with no set-theoretic assumptions"
8. Choice function: "If X is a finite set of nonempty sets, then one can construct a choice function for X by picking one element from each member of X. This requires only finitely many choices, so neither AC or ACω is needed."
9-10. MO: In addition to answer 1, see JDH's comment.
11-16. Math.SE: See answers 1-5 (and many of the comments): 1: "Knowing that S is non-empty, there do exist such x, and so we can declare the symbol x to denote an element of S, and the rest of our argument is then a function of x."; 2: "The ability to give a name to some arbitrary element of a nonempty set is known as "existential instantiation". This is an inference rule of the underlying logic, not part of the theory, and so it is included not only in ZFC, but also in ZF, and in appropriate forms it is also included in PA and every other first-order theory."; 4: "The axiom of choice, as said, allows us to choose from infinitely many sets at once (sometimes even when these sets are finite!). If, however, one only wishes to choose from finitely many sets then this can be done without it. It does not even matter if the sets themselves are finite or not."
17-22. Math.SE: See answers 1-6. 1: "It's a matter of the basic rules of inference allowed in proofs." 3: "the main answer is that making a single choice out of a single bin is a matter of logic. Specialized to this particular situation, if S is a set and you have proven ∃x:x∈S, then logic allows you to introduce a new constant symbol (say, a) along with the corresponding an axiom a∈S."
23. Quora: "The axiom of choice is still required to prove that a choice function exists for an infinite family of finite sets. That a choice function exists for a finite family of sets (of whatever size) can be proven in ZF without the axiom of choice."
24. Math.SE: First answer.
25-28. Math.SE: See answers 1-4.
29. Math.SE: See first answer: "No, you're not. The axiom of choice isn't relevant for making one single choice. The axiom of choice only becomes relevant when you have to make infinitely many choices."
30-32. Math.SE: See first answer + comments of Bananach and Asaf ("Choosing one element from a provably non-empty set has nothing to do with the axiom of choice, and everything to do with the inference rules of your logic.")
33. Math.SE: First answer.
34-35. Math.SE: See answers 1-2. "As you can see, no AC used here, because (morally) you don't need it to pick exactly one element from a set."
36. Quora: "just map it to some fixed, arbitrarily chosen element of A. There seems to be “choice” involved here, but in fact it is trivial: you need to pick just a single element of a single given set."
37. Math.SE: 1st answer: "One direction ... is just true without choice. If there is an injection f:X→Y, then there is always a surjection from Y onto X, … (here we used the fact that X is non-empty)."
38. Axiom of choice, at least three places in the page text: "In many cases, such a selection can be made without invoking the axiom of choice; this is in particular the case if the number of sets is finite", "… the axiom of choice … thus implies that every finite collection of nonempty sets has a choice function. However, that particular case is a theorem of the Zermelo–Fraenkel set theory without the axiom of choice (ZF); it is easily proved by mathematical induction.[6] In the even simpler case of a collection of one set, ... the axiom of choice says that every nonempty set has an element; this holds trivially.", "For finite sets X, the axiom of choice follows from the other axioms of set theory. In that case it is equivalent to saying that if we have several (a finite number of) boxes, each containing at least one item, then we can choose exactly one item from each box."
2601:42:0:4C76:7465:467D:C2F9:6CEE (talk) 07:12, 8 September 2018 (UTC)
I have a degree in mathematics, so I know what an injection is.
However, the people looking up "injection" on Wikipedia are looking up "injection" because they do not know what an it is.
Currently, the article is only readable to mathematicians.
You can tell by using the following rule:
If a person does not know what is, then they probably do not know what and are either.
The only way for a non-mathematician to understand mathematical thing is to define using only terms found in everyday English.
The follow should not be the opening line of the article. The opening line of article to be readable to both mathematicians and non-mathematicians alike.
Problem:
The following is also not accessible to the general public:
Something like this is more readable to non-mathematicians:
In everyday English, the word "image" is usually you something you imagine seeing/visualizing in your mind. For example, "The author uses vivid language to create the image of a dragon in the reader's mind" An image can also be a painting, photograph/. Also, "The image of an oncoming car was still burned into her retinas" In English, an "image" is not the output of a function. In mathematics, the "image" of is . In English, the image of is what you see with your eyes, which includes information other than the smallest set containing all possible output.
I am hoping that the article on injection can be split into two sections:
Those are NOT the names I would use for the sections. Feel free to suggest some better names for the sections. However, that is how I recommend that the content be sorted.
73.153.60.76 (talk) 04:41, 11 July 2021 (UTC)
You've gotta be kidding me. How long has this article been so clumsy? The images were misplaced, making the article practically unreadable. I've moved them to the gallery section and included a link to this section in both the lead and "examples" section. This will make the article much more presentable. As a result, I have gone ahead and re-assessed this article, changing its rating from start to a C class article. There is still much work to do, but this will be a start. SpiralSource (talk)
If "univalent function" is essentially a synonym for "injective function" in complex analysis, should it be merged here? (Not to be confused with univalent relation, which is a kind of binary relation.) Apocheir (talk) 21:36, 31 August 2022 (UTC)
Not sure if this is intentional, but the image displayed in the thumbnail when you Google injective map is not correct. It shows the example "A non-injective non-surjective function (also not a bijection)". Is it possible to change this? AcuteTriceratops (talk) 19:02, 15 October 2022 (UTC)